# 52 continued g h2 o l fp v 1 f l f l 2 from a

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Unformatted text preview: ft/s for NOR PAC, uV = uo f = 12.0(0.7) = 8.4 ft/s for Montz. 2 For NOR PAC, uo = 0.21 4VM V From Eq. (6-103), column diameter = DT = fu0 V 4(1495 / 3600)(30.9) For NORPAC, DT = 13(3.14)(0.0689) 1/ 2 1/ 2 4VM V = uV V 1/ 2 = 4.3 ft. 1/ 2 4(1495 / 3600)(30.9) For Montz, DT = = 5.3 ft 8.4(3.14)(0.0689) Column diameter based on conditions at the bottom of the column, where T = 207oF and P = 15.5 psia = 1.05 atm. Use Figs. 6.36a, b, and c to compute flooding velocity, following Example 6.13. From the ideal gas law, V = PMV/RT = (1.05)(18.1)/[0.730(207 + 460)] = 0.039 lb/ft3 For the liquid, which is mainly water, use L = 1.00 g/cm3 = 62.4 lb/ft3 and L = 0.27 cP. LM L The abscissa in Fig. 6.36a = X = VM V V L 1/ 2 2569.7(18.1) 0.039 = 1367.8(18.1) 62.4 1/ 2 = 0.047 From Fig. 6.36a, Y at flooding = 0.17; from Fig. 6.36b, for water/ L = 1/1 = 1, f{L }= 1; and from Fig. 6.36c, for L = 0.27 cP, f{L } = 0.77. From Table 6.8, FP = 14 for NOR PAC and FP = 33 for Montz. g H2 O (L) 1 2 From a rearrang...
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