55 subject determining compositions and energy

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Unformatted text preview: e two feeds are adiabatically mixed, the resulting two-phase mixture contains the following, where it is necessary to convert mass to moles. Component nC6 nC8 Total MW 86.11 114.14 Feed F1 : lb 232 718 950 lbmol 2.69 6.29 8.98 Feed F2 : lb 845 280 1,125 lbmol 9.81 2.45 12.26 Total feeds: lbmol 12.5 8.74 21.24 mole fraction 0.5885 0.4115 100 Based on the mole fractions of the combined feed, point M, the adiabatic mixing point is located in Fig.7.37 on the next page. By coincidence the mixing line connecting the two feeds is also a tie line for a temperature of 204oF. The equilibrium vapor is located at point V, while the equilibrium liquid is located at point L. The equilibrium vapor has a mole fraction of 0.75 for nC6 and 0.25 for nC8. The equilibrium liquid has a mole fraction of 0.35 for nC6 and 0.65 for nC8. Although not requested, the moles of equilibrium vapor and liquid can be determined by material balances. By total material balance, F1 + F2 = 21.24 = V + L (1) By material balance...
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This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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