# 6 and for the slope of 0446 095 y095 06 y 0794

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Unformatted text preview: mol/h and V' = V = 180.5 kmol/h Therefore, the middle section operating line has a slope of L'/V' = 163.8/180.5 = 0.908 and intersects the q-line for x = 0.6 at y = 0.794. It intersects the vertical q-line at x = 0.4 and for the slope of 0.908 = (0.794 - y)/(0.6 - 0.4), y = 0.613. For the lower section, L" = L' + F1 = 163.8 + 125 = 288.8 kmol/h and V"=V' = 180.5 kmol/h Therefore, the lower section operating line has a slope of L"/V" = 288.8/180.5 = 1.60 and intersects the q-line for x = 0.4 and y = 0.613. As seen in Fig. 7.27(c), the mole fraction of A in the bottoms, xB , is determined from the intersection of the operating line for the lower section with the y-axis. Thus, 1.60 = (0.613 - 0)/(0.4 - xB). Solving, xB = 0.0169 for component A. Since the bottoms contains 5 kmol/h of A, the bottoms rate = B = 5/0.0169 = 295.9 kmol/h. Thus, the bottoms contains 290.9 kmol/h of water. But, the flow rate of water entering in the two feeds = 125 + 83.3 - 100 = 108.3 kmol/h. Therefore, the o...
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