# 639 v dv 0052 0171 254 2 12 2 from eq 6 133 with

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Unformatted text preview: = 382 K and liquid viscosity = 0.25 cP. This time, benzene is component A and toluene is B. From Eq. (3-42), T 1.29 (PB0.5 / PA0.5 ) 3821.29 (24550.5 / 205.30.42 ) . DL = DAB = 155 10-8 . = 155 10-8 . = 6.64 10-5 0.92 0.23 0.92 0.23 B B 0.25 118.2 Analysis: (c) bottom of the column (continued) From Eq. (6-132), using SI units Exercise 7.53 (continued) 1 1 HL = CL 12 1/ 6 4hL DL au L 1/ 2 uL a a aPh 1/ 2 1 1 = 1.168 12 1/ 6 4(0.0312)(0.977) (6.64 10 -9 )(92.3)(0.00911) 0.00911 92.3 a a = 0.26 aPh aPh m To compute (aPh /a), we need for the liquid phase, the Reynolds, Weber, and Froude numbers from equations (6-138), (6-139), and (6-140), respectively, based on the packing hydraulic diameter from (6-137). d h = packing hydraulic diameter = 4 0.977 =4 = 0.0423 m = 0.139 ft a 92.3 Reynolds number = N ReL ,h = uL d h L (0.0299)(0.139)(48.7) = = 1205 [(0.25)(0.000672)] L Take the surface tension of toluene at 227oF as = 18 dynes/cm = 0.00123 lbf/ft or 0.00123(32.2) = 0.0397 lbm/s2 Weber numbe...
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## This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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