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Unformatted text preview: he partial reboiler, and 13.8 equilibrium stages in the rectifying section. Analysis: (a) (continued) Exercise 7.51 (continued) Exercise 7.51 (continued)
Analysis: (a) (continued) Exercise 7.51 (continued)
Analysis: (a) (continued) Exercise 7.51 (continued)
Analysis: (continued)
(b) Because the value of HOG is given in part (d), calculate NOG for each section, using from Table 6.7 for EM diffusion, N OG = dy y y
* For the stripping section, the first stage is the partial reboiler. Therefore, from the McCabeThiele diagram, starting from Stage 2, the limits on y are y = 0.09 at x = 0.03 to y = 0.37 at x = 0.10. Using the trapezoidal method to solve the integral, ( NOG )SS = y (0.23  0.09) (0.37  0.23) = + = 2.4 0.10 0.14 ( y * y) For the rectifying section, the limits on y are y = 0.37 at x = 0.1 to y = 0.80. Using the trapezoidal method to solve the integral, ( NOG ) RS = y (0.42  0.37) (0.665  0.42) ( 0.80  0.665 ) = + + = 12.4 0.084 0.063 0.017 ( y *y) (c) For 15.8 equilibrium sta...
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This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .
 Spring '06
 selebi
 Distillation, pH, Mass Transfer

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