# Ch07

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Unformatted text preview: W 3 1 - DT 3 1 - 0.977 3.6 Therefore, KW = 1/1.039 = 0.962 Superficial gas velocity at 70% of flooding from above = 5.9 ft/s Gas viscosity = 0.0092 cP and gas density = 0.179 lb/ft3. Exercise 7.53 (continued) Analysis: (e) Stripping section (continued) From Eq. (6-105), N ReV = uV DP V (5.9)(0.0049)(0.179) (0.962) = 35, 000 KW = (1 - ) V (1 - 0.977 ) (0.0092)(0.000672) 64 1.8 64 1.8 + 0.08 = 0.421 + = 0.329 35, 000 35, 0000.08 N ReV N ReV From Eq. (6-104), o = C p From Eq. (2), Po 92.3(0.3048) 5.9 2 (0.179) 1 = 0.329 = 1.0 lbf/ft3 or 0.0069 psi/ft 3 0.977 2(32.2) 0.962 lT From Eq. (1), with hL = 0.0412 m3/m3 and liquid Froude number = 7.80 x 10-4 P 0.977 - 0.0412 = 0.0069 lT 0.977 3/ 2 exp 1/ 2 13300 7.80 10-4 ) = 0.0098 psi/ft 3/ 2 ( 92.3 From these results, the column diameter would be 4.0 ft without swaging. Take the packed height as 14 ft. The column height, allowing 4 ft for disengagement, 2 ft for feed entry, and 10 ft for sump at the bottom would be 30 ft. The total pressure drop is: (2.31/0....
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## This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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