# 93 lbft3 and liquid density l 270 lbft3 analysis

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Unformatted text preview: 27.0 0.5 = 0.343 Assume 24-inch tray spacing. From Fig. 6.24, CF = 0.22 From below Eq. (6-44), Ad/A = 0.1+ (0.343 - 0.1)/9 = 0.127 Assume surface tension, , = 10 dyne/cm. From below Eq. (6-42), FST = (10/20)0.2 = 0.87 Assume that the foaming factor, FF = 1.0 and take FHA = 1.0. From Eq. (6-42), C = 0.87(1.0)(1.0)(0.22) = 0.19 ft/s - V From Eq. (6-40), U f = C L V From Eq. (6-44), 4VM V DT = fU f (1 - Ad / A)V 1/ 2 1/ 2 27.0 - 2.93 = 019 . 2.93 0.5 = 0.55 ft / s 4(5, 931/ 3600)(44.1) = 0.85(0.55)(3.14)(1 - 0.127)(2.93) 0.5 = 8.8 ft Tray Efficiencies: Use Fig. 7.32. Need relative volatility and average liquid viscosity. From Fig. 2.8, K-values and relative volatilities are: Component K-value at 116oF, 280 psia K-value at 136oF, 300 psia Propylene 1.00 1.14 Propane 0.87 1.00 At the top, = 1.00/0.87 = 1.15. At the bottom, = 1.14/1.00 = 1.14 At the top, propylene viscosity = 0.45 cP. At the bottom, propane viscosity = 0.44 cP. At the top, = 1.15(0.45) = 0.52. From Fig. 7.32, Eo = 60%. At the bo...
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## This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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