# A flow rate equal to that of he leakage passes out

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Unformatted text preview: out the bottom of the column. In normal operation, the water passing out in the distillate = 0.1(53) = 5.3 kmol/h, while for the abnormal operation, the water passing out in the distillate = 0.2(53) = 10.6 kmol/h. Thus, an additional 5.3 kmol/h of water leaves in the distillate. For the abnormal operation, the overhead vapor rate = 53 + 94 = 147 kmol/h and, therefore, 53/147 x 100% = 36% of the overhead vapor (total condensate) is distillate. Thus, if 15 kmol/h of water leaked into the overhead vapor, then, we would expect 0.36(15) = 5.4 kmol/h would be expected to leave with the distillate. This compares very well with the 5.3 kmol/h additional water calculated above by material balance. If the degree of fractionation within the column is about the same as for the normal operation, it could be concluded that a condenser cooling water leak is to blame. To check the cooling water leak, could meter the cooling water in and out of the condenser and see if there is a difference. If the vapor rate is kept constant and the refl...
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## This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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