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Unformatted text preview: Power output = [Power input] x [efficiency] Power input = [Power output]/[efficiency] = 2.6e6W/0.3 = 8.67e6 W A = Power/I = (8.67e6W)/(1100 W/m^2) = 7880 m^2 I = I max cos 2 θ => θ = acos(I/I max ) 1/2 a. (I/Imax) = (1/2.4), θ = acos(0.645) = 49.8 degrees etc. The average value of the cosine squared function is onehalf, so the first polarizer transmits ½ the light. The second transmits cos 2 25 o = 0.822. So we have (0.822/2) = 0.411...
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This note was uploaded on 09/08/2008 for the course PHYS 3B taught by Professor Wu during the Spring '08 term at UC Irvine.
 Spring '08
 Wu
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