ch01_p39 - 39. (a) For the minimum (43 cm) case, 9 cubit...

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39. (a) For the minimum (43 cm) case, 9 cubit converts as follows: () 0.43m 9cubit 9cubit 3.9m. 1cubit §· == ¨¸ ©¹ And for the maximum (43 cm) case we obtain 0.53m 9cubit 9cubit 4.8m. 1cubit (b) Similarly, with 0.43 m 430 mm and 0.53 m 530 mm, we find 3.9 × 10 3 mm and 4.8 × 10 3 mm, respectively. (c) We can convert length and diameter first and then compute the volume, or first
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This note was uploaded on 09/09/2008 for the course PHYS 100 taught by Professor Shylnov during the Spring '08 term at Illinois Tech.

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