This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Problem 294/12 (a) The parameter of interest is =true average braking distance at 40 mph for the new design . The hypothesis are H : = 120 vs H a : < 120. (b) E ( x ) ( = 120 , if H is true, < 120 , if H a is true. Hence R 2 should be used. (c) X = n = 10 6 = 1 . 6667, so = P ( R 2 when H is true) = P ( X 155 . 20when = 120) = P ( X 120 1 . 6667 115 . 20 120 1 . 6667 ) = N ( 2 . 88; 0 , 1) = 0 . 002 . To obtain = 0 . 001, we need to replace 115.20 by a number c such that P ( X c when = 120) = N ( c ; = 120 , X = 1 . 6667) = 0 . 001. Hence, we use JMP to compute c = Normal Quantile(0.001,120,1.667) = 114 . 87. (d) P (accepting H when = 115) = P ( X 115 . 20when = 115) = P ( X 115 1 . 6667 115 . 20 115 1 . 6667 ) = 1 N (0 . 12; 0 , 1) = 0 . 4522. For the first region, = P ( Z  2 . 33) = N ( 2 . 33; 0 , 1) = 0 . 01. For the second region, = P ( Z  2 . 88) = 0 . 002. Problem 305/24 = true average viscosity. H : = 3000 vs H a : 6 = 3000. t obs = x 3000 s/ n = 2887 . 6 3000 84 / 5 = 2 . 99. At level , the rejection region is  t obs  = 2 . 99 > t 2 , 4 . For example, using the table below, we can see that we reject at = 0 . 05 but dont reject at = 0 . 01. Hence, the requirement is not satisfied at = 0 . 05. On the other hand, theres no evidence that indicates that the requirement is satisfied at = 0 . 01. (For the homework, it suffices to report the test for your favorite choice of ). 1 Problem 311/44 p = proportion of defectives, by robots. H : p = 0 . 035 vs H a : p < . 035. We use z obs = p . 035 (0 . 035)(0 . 965) / 500 = z obs = 15 500 . 035 (0 . 035)(0 . 965) / 500 = . 005 . 0082 = . 61....
View
Full
Document
This note was uploaded on 09/09/2008 for the course ENGRD 2700 taught by Professor Staff during the Summer '05 term at Cornell University (Engineering School).
 Summer '05
 STAFF

Click to edit the document details