{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Fa06Soln4 - Physics 7B Fall 2006 Homework 4 Solutions...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Physics 7B Fall, 2006 Homework 4 Solutions 20.30 ( a ) For a Carnot refrigerator, we have Q H = nRT H ln( V b / V a ) = nRT H ln( V b / V a ); Q L = nRT L ln( V d / V c ) = nRT L ln( V c / V d ) = nRT L ln( V b / V a ), because V c / V d = V b / V a ; W = Q H Q L . The coefficient of performance is CP = Q L / W = Q L /( Q H Q L ) = nRT L ln( V b / V a )/[ nRT H ln( V b / V a ) – nRT L ln( V b / V a )] = T L /( T H T L ) . ( b ) The efficiency of the reversible heat engine is e = 1 – ( T L / T H ), so T L / T H = 1 – e . Thus we have CP = T L /( T H T L ) = ( T L / T H )/[1 – ( T L / T H )] = (1 – e )/ e . ( c ) The coefficient of performance is CP = T L /( T H T L ) = (257 K)/(295 K – 257 K) = 6.8 . 20.31 The power input is P = W / t = Q L /(CP) t = mL /(CP) t = ρ VL /(CP) t ; 1000 W = (1.00 × 10 3 kg/m 3 ) V (3.33 × 10 5 J/kg)/(7.0)(3600 s), which gives V = 7.6 × 10 –2 m 3 = 76 L . 20.36 ( a ) The change in entropy of the water is Δ S water = Q / T = mL / T = – (1.00 kg)(539 kcal/kg)/(373 K) = + 1.45 kcal/K . ( b ) Because the heat to vaporize the water comes from the surroundings, we have Δ S surr = – Q / T = – 1.45 kcal/K . ( c ) For the universe we have Δ S universe = Δ S water + Δ S surr = + 1.45 kcal/K + (– 1.45 kcal/K) = 0 .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern