Fa06Soln1 - Physics 7B Fall 2006 Homework 1 Solutions 17.8...

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Unformatted text preview: Physics 7B Fall, 2006 Homework 1 Solutions 17.8 At any temperature below 20°C the expansion cracks will increase. Thus the expansion from 20°C to 50°C must eliminate the cracks. Any higher temperature will cause stress in the concrete. If the cracks have a width Δ L , we have Δ L = α L Δ T = [12 × 10 –6 (C°) –1 ](12 m)(50°C – 20°C) = 4.3 × 10 –3 m = 0.43 cm . 17.14 ( a ) The expansion of the container causes the enclosed volume to increase as if it were made of the same material as the container. The volume of water that was lost is Δ V = Δ V water – Δ V container = V β water Δ T – V β container Δ T = V ( β water – β container ) Δ T ; (0.35 g)/(0.98324 g/mL) = (55.50 mL)[210 × 10 –6 (C°) –1 – β container ](60°C – 20°C), which gives β container = 50 × 10 –6 (C°) –1 . ( b ) From Table 17–1, copper is the most likely material. 17.35 If we assume argon is an ideal gas, we have PV = nRT = ( m / M ) RT ; P (35.0 × 10 –3 m 3 ) = [(105.0 kg)(10 3 g/kg)/(40 g/mol)](8.315 J/mol · K)(293 K), which gives P = 1.83 × 10 8 Pa = 1.80 × 10 3 atm ....
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Fa06Soln1 - Physics 7B Fall 2006 Homework 1 Solutions 17.8...

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