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Unformatted text preview: Physics 7B Fall, 2006 Homework 1 Solutions 17.8 At any temperature below 20C the expansion cracks will increase. Thus the expansion from 20C to 50C must eliminate the cracks. Any higher temperature will cause stress in the concrete. If the cracks have a width L , we have L = L T = [12 10 6 (C) 1 ](12 m)(50C 20C) = 4.3 10 3 m = 0.43 cm . 17.14 ( a ) The expansion of the container causes the enclosed volume to increase as if it were made of the same material as the container. The volume of water that was lost is V = V water V container = V water T V container T = V ( water container ) T ; (0.35 g)/(0.98324 g/mL) = (55.50 mL)[210 10 6 (C) 1 container ](60C 20C), which gives container = 50 10 6 (C) 1 . ( b ) From Table 171, copper is the most likely material. 17.35 If we assume argon is an ideal gas, we have PV = nRT = ( m / M ) RT ; P (35.0 10 3 m 3 ) = [(105.0 kg)(10 3 g/kg)/(40 g/mol)](8.315 J/mol K)(293 K), which gives P = 1.83 10 8 Pa = 1.80 10 3 atm ....
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