1311ex4_f05 - k = 1.3807 x 10-23 J K-1 R = 0.082057 l atm...

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M M M k = 1.3807 x 10 -23 J K -1 R = 0.082057 l atm mol -1 K -1 = 8.314 J mol -1 K -1 = 1.987 cal mol -1 K -1 = 8.314 V C mol -1 K -1 k= R / N A N A = 6.022 x 10 23 mol -1 1 kcal = 4.184 kJ c = 2.998 x 10 8 m s -1 c = λν E = -13.6(Z/n) 2 eV 1 eV = 1.6022 x 10 -19 J 1 eV = 96.485 kJ mol -1 E = h ν χ = (IE+EA)/2 Δ E = -2.18 x 10 -8 J (Z 2 ) (1/n 2 f - 1/n 2 i ) E = -me 4 Z 2 /8 ε o n 2 h 2 E= mc 2 λ = h/mv 1 nm = 10 -9 m 1 D = 10 -8 cm=100 pm ε o = 8.85 x 10 -12 J -1 C 2 m -1 4 πε o = 1.113 x 10 -10 C 2 J -1 m -1 U % N A q + q - e 2 M/r o Δ G = Δ H - T Δ S = -RTlnK Δ G E = -n F E E EE RT n ln [products] [reactants] =− o F
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E s s p p F F F F * B B * (n-1) d n s n p ) L orbitals F * F F F F * F * n t 2g e g * I < Br < Cl < S CN < F , OH < NO 2 < H 2 O < SCN < NH 3 < en < N O 2 < PR 3 < P(OR) 3 , C 2 H 4 < PF 3 , CO, CN
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M M Name____________________________________ Chem 1311 Fourth Exam 2 December 2005 In taking this examination, you are expected to adhere to the GT academic honor code. At a minimum this requires that you utilize only the materials supplied to you, and that you do not give help to, or accept help from, others. Calculators and other electronic devices are not allowed. 1. (4) Draw the structure of the anticancer drug cis -dichlorobisammineplatinum(II) (also known as cisplatin). 2. (12) Covalent interactions of ligands with transition metal ions can have dramatic effects on the energy separation of the two groups of d orbitals in an octahedral complex.
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This note was uploaded on 09/09/2008 for the course CHEM 1311 taught by Professor Soper during the Spring '08 term at Georgia Institute of Technology.

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1311ex4_f05 - k = 1.3807 x 10-23 J K-1 R = 0.082057 l atm...

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