equations04su_b

# equations04su_b - 1 revolution = 360° = 2π rad 2 2 32 8 9...

This preview shows page 1. Sign up to view the full content.

Useful Equations for Physics 211 Last Updated 7/18/07 t x x av v = _ dt r d v x = t v x av x a = _ dt v d a = t a v v x ix fx + = t v v x fx ix + = ) ( 2 1 2 2 1 t a t v x x ix + = x a v v x ix fx + = 2 2 2 t av = θ ϖ dt d θ ϖ = t av = ϖ α dt d ϖ α = t i f + = α ϖ ϖ t f i + = ) ( 2 1 ϖ ϖ θ 2 2 1 t t i + = α ϖ θ θ α ϖ ϖ + = 2 2 2 i f T r v π 2 = ϖ π rad 2 = T 2 2 ϖ r a a r v r c = = = α r a dt v d t = = θ = r s ϖ r v = α r a t = dt p d a m F x = = ( 29 t p av F = A on B B on A F F - = w = mg N f s s μ N f k k μ = x k F Spring - = | F spring | = k | x | dx dU x F - = dt L d I x x = = α τ ( 29 t L av = τ A on B B on A τ τ - = F r x x x × = τ Fd rF = = φ τ sin A B B P A P v v v + = V m = ρ dx dU x F - = = i i i r m I 2 points = dm r I 2 2 Md I I CM + = v m p x x = f tot i tot P P _ _ s s = cm tot tot v M P x x = ( 29 Σ = - = f i t t i f dt F p p J p r L x x x × = point pd rp L = = φ sin point ϖ I L = rotating f tot i tot L L _ _ s s = M x m CM i i i x = M y m CM i i i y = ϖ ϖ I Mgr I wr precession = = 2 2 1 mv K tr = 2 2 1 ϖ I K rot = mgh U grav = 2 2 1 kx U spring = f f i i nc U K U K W + = + + K W net = = f i s s s d F W = f i d W θ θ θ τ θ cos Fs W = θ τ = W dt dW P = t W t E av P = = θ cos Fv v F P = = τ ϖ = P Useful Constants/Conversion Factors:
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 revolution = 360° = 2π rad 2 2 32 8 . 9 s ft s m g = = lb N s m kg 225 . 1 1 2 = = ⋅ 1 J = 1 N∙m = 0.239 cal 1 W = 1 J/s = 1.34×10-3 hp 1 kg weighs 2.205 lb near the earth’s surface Circle: Circumference=2πr Area=πr 2 Sphere: Area= 4π r 2 Volume=(4/3)π r 3 Cylinder: Area=2πrh Volume= πr 2 h...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern