This preview shows pages 1–5. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: _ 91m: ’oe
we; gem Sent 1 1 .1 1 The acceleration of point A is deﬁned by the relation a = —3.24
sin kt — 4.32 005 kt, where a and t are expressed in st£ and seconds, re
spectively, and]: = 3 rad/s. Knowing that x = 0.48 ft and v = 1.08 ft/s when
t = 0, determine the velocity and position of point A when t = 0.5 s. as g} 11.24 The acceleration of a 7 particle is deﬁned by the relation
:1 = —k02, Where a is expressed in m/s2 and v in m/s. The particle starts at
x = 0 with a velocity of 9 m/s and when x = 13 m the velocity is found to be
7 m/s. Determine the distance the particle will travel (a) before its velocity drops to 3 m/s, ([9) before it comes to rest. g, ereewg‘ﬁ Welt?“ wee? ii: : i
{it a? E31; 53
t g _ § 5 L {3% {31); ggﬁﬁ as {4% as: we; g a} ‘ fete}? 3% we?” ﬁixggéﬂ
a 'w a: '5‘
v ‘0 Wu H .30 Based on observations, the speed of a jogger can be approximated
by the relation 1) = 7.5(1  0.041003, where v and x are expressed in km/h and
kilometers, respectively. Knowing that x = 0 at t = 0, determine (a) the distance
the jogger has run when t = 1 h, (b) the jogger’s acceleration in m/s2 at t = 03
(C) the time required\for the jogger to run 6 km. W ' / 1% Li a
n .‘a xee redw~§§w
35 i 0 04a Mfr
jdx/ ej’ meleﬂ‘;
MN? " «we?
{zeotamp aw ELM (:57;
25' Cl—G'Q‘itll ; gigg
are;
to
g» A ,_ 3‘? {We : &
é§£3"0.6442i@] ‘" xii; 3226’} » égzw)
 M Fig. P11 .30 // 1 1.34 The velocity of a particle is v = OOH — 31:10:72]! T)]. Knowing that '
the particle starts from the origin withan initial velocity D0, determine (a) its position and its acceleration at t =
intervalt = 0 tot = T. 3T, ([9) its average velocity during the l ...
View Full
Document
 Fall '08
 MOORTHY

Click to edit the document details