~ hw2_sol

~ hw2_sol - _ 91m: ’oe we; gem Sent 1 1 .1 1 The...

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Unformatted text preview: _ 91m: ’oe we; gem Sent 1 1 .1 1 The acceleration of point A is defined by the relation a = —3.24 sin kt — 4.32 005 kt, where a and t are expressed in st£ and seconds, re- spectively, and]: = 3 rad/s. Knowing that x = 0.48 ft and v = 1.08 ft/s when t = 0, determine the velocity and position of point A when t = 0.5 s. as g} 11.24 The acceleration of a 7 particle is defined by the relation :1 = —k02, Where a is expressed in m/s2 and v in m/s. The particle starts at x = 0 with a velocity of 9 m/s and when x = 13 m the velocity is found to be 7 m/s. Determine the distance the particle will travel (a) before its velocity drops to 3 m/s, ([9) before it comes to rest. g, ereewg‘fi Welt?“ wee? ii: : i {it a? E31; 53 t g _ § 5 L {3% {31); ggfifi as {4% as: we; g a} ‘ fete}? 3% we?” fiixggéfl a 'w a: '5‘ v- ‘0 Wu H .30 Based on observations, the speed of a jogger can be approximated by the relation 1) = 7.5(1 - 0.041003, where v and x are expressed in km/h and kilometers, respectively. Knowing that x = 0 at t = 0, determine (a) the distance the jogger has run when t = 1 h, (b) the jogger’s acceleration in m/s2 at t = 03 (C) the time required\for the jogger to run 6 km. W ' / 1% Li a n .‘a xee redw~§§w 35 i 0 04a Mfr jdx/ ej’ melefl‘; MN? " «we? {zeotamp aw ELM (:57; 25' Cl—G'Q‘itll ; gig-g are; to g» A ,_ 3‘? {We : & 駣3"0.6442i@] ‘" xii; 3226’} » égzw) - M Fig. P11 .30 // 1 1.34 The velocity of a particle is v = OOH — 31:10:72]! T)]. Knowing that ' the particle starts from the origin withan initial velocity D0, determine (a) its position and its acceleration at t = intervalt = 0 tot = T. 3T, ([9) its average velocity during the l ...
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~ hw2_sol - _ 91m: ’oe we; gem Sent 1 1 .1 1 The...

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