3001010001 forcross2coc8002004010001

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Unformatted text preview: &E: AC: (54+66+38+42)/1000*100% = 20 mu CE: (163+157+38+42)/1000*100% = 40 mu The map that accommodates all the data is: E40C20A30B10D Coefficient of coincidence = [(obs DCO)/(exp DCO)] For cross 1: COC = {30/[(0.30)(0.10)(1000)]}=1 For cross 2: COC = {80/[(0.20)(0.40)(1000)]}=1 Since interference = 1COC, interference is zero for all crosses, so no evidence of interference. 2. The following table shows the map distances between 6 different genes. Construct a genetic map that includes all 6. Nl Ri Lw Rl Ac Sn Nl 2 23 7 11 12 Ri 2 25 9 9 14 Lw 23 25 16 34 11 Rl 7 9 16 18 5 Ac 11 9 34 18 23 Sn 12 14 11 5 23 Ac9Ri2Nl7Rl5Sn11Lw 3. Exploring Genomics, Chapter 5 (page 134). Exercise I, p...
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