FINAL Key - 2 / 2 mol HCl) = 0.162 mol P = (0.162 mol)( R...

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CHEM 201- 20 June 30, 2006 FINAL EXAM KEY Part 1 1. F, T, F, T, F, F, T 2. O > Be > K; O > Be > K; O < Be < K 3. Cu + , Zn, Zn 2+ 4. Zn 2+ ; [Ar] 4s 1 3d 5 ; 3d; n=2, l=1, m l = -1, 0, 1 ; n=3, l=1, m l =0, m s = + ½ 5. greatest MgO; least RbI 6. – 105 kJ 7. a) H – C (triple bond) N: b) H – O – C = O (and two lone pairs on | each oxygen) O – H 8. complete answer should have included both structures, with formal charges 0 0 0 0 -1 +1 F – B – F vs. F – B = F (and lone pairs on all F | | to fill octets) F Preferred! F 9. a) Bent shape; polar molecule b) Trigonal bipyramidal; non-polar (P-Cl dipoles cancel) c) linear; non-polar (C=O dipoles cancel) class shape 10. H – C – H C AX 3 trigonal planar trig. planar || :N N AX 2 E trig. Planar Bent (V) | :O: O AX 2 E 2 tetrahedral Bent | H Bonus: due to LP and double bonds- NO ideal angles
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Part 2 1. a) x mol HCl = 16.2 g CaCO 3 (1mol/100.09g)(2mol HCl/1mol CaCO 3 ) = 0.323 mol L HCl = mol / Molarity = 0.323 mol / 0.383 M = 0.845 L = 845 mL b) use PV = nRT, need to first find gas mols from CO 2 (g) mol CO 2 = 0.323 mol HCl (1 mol CO
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Unformatted text preview: 2 / 2 mol HCl) = 0.162 mol P = (0.162 mol)( R )(295 o K) / 0.500L = 7.85 atm 2. – q rxn = q h2o + q calorimeter = (mass x c h2o x ∆ T) + (Heat capacity x ∆ T)- (- 3227 kJ/mol)(0.1000 mol) = (1200g x 4.184 J/g o K x 50.31) + ( HC x 50.31) Heat capacity of the calorimeter = 1400 J/ o K 3. a) 2 MnO 4-(aq) + 10 Cl-(aq) + 16 H + (aq) 5 Cl 2 (g) + 2 Mn 2+ (aq) + 8 H 2 O 2 (Mn 7+ O 4-+ 5e- Mn 2+ ) Reduction 5 ( 2 Cl -1 Cl 2 + 2e-) Oxidation b) mol Cl- = mol KMnO 4 ( 10 mol Cl-/ 2 KMnO 4 ) = ( 0.00371 L x 0.122 M KMnO 4 ) ( 10 mol Cl-/ 2 KMnO 4 ) = 0.00226 mol Cl-M Cl-= 0.00226 mol Cl-/ 0.100 L water sample = 0.0226 M 4. a) υ = 1.2 x 10 11 s-1 ; E = 8.0 x 10 -23 J b) υ = 1.2 x 10 19 s-1 ; E = 8.0 x 10 -15 J 5. P O2 = P Total x X O2 = (0.89 atm ) (0.2094) = 0.19 atm n O2 = P O2 V / RT = (0.19 atm)(10 L) / ( 0.0821 atm . L /mol . o K )( 268 o K ) n O2 = 0.086 mol...
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This note was uploaded on 09/12/2008 for the course CHEM 201 taught by Professor Hoyt during the Spring '07 term at University of Louisville.

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FINAL Key - 2 / 2 mol HCl) = 0.162 mol P = (0.162 mol)( R...

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