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Unformatted text preview: Gozick, Brandon Homework 16 Due: Nov 7 2006, 7:00 pm Inst: D Weathers 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points A particle of mass 0 . 11 kg is attached to the 100cm mark of a meter stick of mass . 11 kg. The meter stick rotates on a horizon tal, frictionless table with an angular speed of 2 . 5 rad / s. Calculate the angular momentum of the system when the stick is pivoted about an axis perpendicular to the table through the 50cm mark. Correct answer: 0 . 0916667 kg m 2 / s. Explanation: L = I The moment of inertia of the stick is I s = 1 12 m s (1 m) 2 and of the particle at tached to the stick I p = m p 1 2 m 2 . The total moment of inertia of the system is I 1 = I s + I p = 1 12 (0 . 11 kg) (1 m) 2 + (0 . 11 kg) 1 2 m 2 = 0 . 0366667 kg m 2 , and the angular momentum is L 1 = I 1 = (0 . 0366667 kg m 2 )(2 . 5 rad / s) = 0 . 0916667 kg m 2 / s . 002 (part 2 of 2) 10 points Calculate the angular momentum of the sys tem when the stick is pivoted about an axis perpendicular to the table through the 0cm mark. Correct answer: 0 . 366667 kg m 2 / s. Explanation: The moment of inertia of the stick in this case is I s = 1 3 m s (1 m) 2 and of the particle attached to the stick I p = m p (1 m) 2 . The total moment of inertia of the system is I 2 = I s + I p = 1 3 (0 . 11 kg) (1 m) 2 + (0 . 11 kg (1 m) 2 = 0 . 146667 kg m 2 , and the angular momentum is L 2 = I 2 = (0 . 146667 kg m 2 )(2 . 5 rad / s) = 0 . 366667 kg m 2 / s . keywords: 003 (part 1 of 1) 10 points A solid cylinder of mass M = 14 kg, radius R = 0 . 48 m and uniform density is pivoted on a frictionless axle coaxial with its symmetry axis. A particle of mass m = 1 . 4 kg and initial velocity v = 15 m / s (perpendicular to the cylinders axis) flies too close to the cylinders edge, collides with the cylinder and sticks to it. Before the collision, the cylinder was not ro tating. What is its angular velocity after the collision? Correct answer: 5 . 20833 rad / s. Explanation: Basic Concept: Conservation of Angu lar Momentum, L particle z + L cylinder z = const ....
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