{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Homework 5

# Homework 5 - Gozick Brandon Homework 5 Due 5:00 pm Inst D...

This preview shows pages 1–2. Sign up to view the full content.

Gozick, Brandon – Homework 5 – Due: Sep 22 2006, 5:00 pm – Inst: D Weathers 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A ball on the end of a string is whirled around in a horizontal circle of radius 0 . 207 m. The plane of the circle is 1 . 03 m above the ground. The string breaks and the ball lands 2 . 37 m away from the point on the ground directly beneath the ball’s location when the string breaks. The acceleration of gravity is 9 . 8 m / s 2 . Find the centripetal acceleration of the ball during its circular motion. Correct answer: 129 . 088 m / s 2 . Explanation: In order to find the centripetal acceleration of the ball, we need to find the initial velocity of the ball. Let y be the distance above the ground. After the string breaks, the ball has no initial velocity in the vertical direction, so the time spent in the air may be deduced from the kinematic equation, y = 1 2 g t 2 . Solving for t , t = r 2 y g . Let d be the distance traveled by the ball. Then v x = d t = d r 2 y g . Hence, the centripetal acceleration of the ball during its circular motion is a c = v 2 x r = d 2 g 2 y r = 129 . 088 m / s 2 . keywords: 002 (part 1 of 1) 10 points Before throwing a 0 . 48 kg discus, an ath- lete rotates it along a circular path of radius 1 . 03 m. The maximum speed of the discus is 8 . 16 m / s. Determine the magnitude of its maximum radial acceleration.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}