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Unformatted text preview: Gozick, Brandon – Homework 20 – Due: Nov 28 2006, 7:00 pm – Inst: D Weathers 1 This printout should have 10 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 5) 10 points The wave function for a linearly polarized wave on a taut string is y ( x,t ) = A sin( ω t k x + φ ) , where A = 0 . 57 m, ω = 4 . 5 s 1 , k = 7 m 1 , φ = 0 . 3, t is in seconds and x and y are in meters. What is the speed of the wave? Correct answer: 0 . 642857 m / s. Explanation: Basic Concepts: v = λ T k = 2 π λ f = ω 2 π Solution: For the propagation speed of a wave we have v = ω k = (4 . 5 s 1 ) (7 m 1 ) = 0 . 642857 m / s . 002 (part 2 of 5) 10 points What is the vertical displacement of the string at x = 0 . 069 m, t = 3 s? Correct answer: 0 . 388797 m. Explanation: We can obtain the result if we simply sub stitute the values for x and t into y ( x,t ) y ( x ,t ) = A sin[ ω t k x + φ ] = (0 . 57 m) sin h (4 . 5 s 1 ) (3 s) (7 m 1 ) (0 . 069 m) + (0 . 3) i = 0 . 388797 m ....
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 Fall '08
 Weathers
 mechanics, Work, Correct Answer, Gozick

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