exam_1A_L07-eq - d , maxima occur where d sin = m , with m...

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Some Equations for Exam 1 sin30 =1 / 2=0 . 5; cos30 = 3 / 2=0 . 87; tan30 =1 / 3=0 . 58 sin60 = 3 / 2=0 . 87; cos60 =1 / 2=0 . 5; tan60 = 3=1 . 73 Some constants: c =3 × 10 8 m/s; e =1 . 6 × 10 - 19 C; 1 / (4 π± 0 )=9 . 0 × 10 9 N · m 2 / C 2 . For light in vacuum: = c . For light in matter: v = c/n . Law of Re±ection: θ incidence = θ refection ; Law of Refraction: n 1 sin θ 1 = n 2 sin θ 2 The Mirror Equation ( r> 0 for concave mirror, r< 0 for convex mirrors): 1 p + 1 i = 2 r . For a thin lens ( f> 0 for converging lenses, f< 0 for diverging lenses): 1 p + 1 i = 1 f . Lateral magni²cation for a mirror or lens: m = - i/p For two thin slits separated by distance d : Maxima occur when d sin θ = with m =0 , ± 1 , ± 2 ,... Minima occur when d sin θ =( m + 1 2 ) λ with m =0 , ± 1 , ± 2 ,... Diffraction for a slit of width a : minima occur where a sin θ = , with m = ± 1 , ± 2 ,... For a diffraction grating with grating spacing
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Unformatted text preview: d , maxima occur where d sin = m , with m = 0 , 1 , 2 , . .. . Rayleighs criterion for a circular aperture of diameter d : R = 1 . 22 /d. Magnitude of the electric eld of a point charge: E = 1 4 q r 2 . Force on a point charge: F = q E . Gauss Law for electricity: E d A = q. Electric potential dierence: V = U q =-final initial E d s . U is the change in potential energy. Energy conservation: K + U = 0. Electric potential for a point charge (under the condition V ( ) = 0): V ( r ) = 1 4 q r ....
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This note was uploaded on 09/13/2008 for the course PHY 317L taught by Professor Ritchie/lang during the Spring '08 term at University of Texas at Austin.

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