Exam2_59955_sol - .» q; "- l. A hollow...

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Unformatted text preview: .» q; "- l. A hollow cylindrical conductor {inner radius 2 a, outer radius = H] carries a current f X" uniformly spread over its cross section tie, the current density is uniform}. Which graph below correctly gives 13' as a function of the distance r from the center of the cylinder? 3 E 3[—| .5“ r — —.— r i" a 5' a :5 a 5* I II lll MEL 3 fl " 2. i j- '. ...-o—-""" -_-_ ___,_..— fl rt if a s t r .I .l . r a b a b -— _. _ '. s -—-t- lit a E J ll A.) l :r. .-t sac-.t. . {3.1163163 r/nfi sink 1:; .I B) It .._—-——r- r: _ he 'HL if I . my c 111 “ " at; "fi—If '1 -. “L y. at ' F - i , —; . ' - nfiu W ,. ' '” ' i” E} V _ I _ LEE-TH ‘1- rl-:' :,..-":' It" . I '.:_F _ I. “I” r. TUE" f r1] "I II p fit-,3 2. Gauss' law for magnetism tells us: " '.,‘-‘ a“: ' 'o'rr { t” A} the net electric charge in any given 1rolmne B] that the line integral of a magnetic field around any closctl loop inust vanish L‘. the magnetic field of a current elctncnt [ __ J, __ H {DJ/that magnetic nlonopolcs do not exist j“; l " ' "" J ME? electric charges must be moving to produce magnetic fields r i” _ M , 1 II I t I n :. _.--..'.. MU. '-' -'.' r '- 3. 1n the circuit shown, hoth resistors have the same value R. Suppose switch S is initially closed. When it is then opened, the circuit has a time constant “ts. Conversely, suppose S is initially open. When it is then ctosctl, the circuit has a ti me constant 1:3. . The ratio saftyis: |., 'i_"‘t‘: 7.. 1- —-- I r.- ., L-'. — ttfii. _‘j ‘9‘) l (a 2 c.) as —r- . ., o) user Lr-w’f'tttf is. E} 1.5 [-'a age '1 4. A clear pelarizct‘ is placed cm top of a similar pclariacr act that their polarizing axes 13: make an angle 01' 3'0” with each ether. The ratio cf the intensity cf emerging light Le incident unpclarizetl light is: 9:3 a I] : gr:- A) 1:4 ; h B} 1:3 “l— -- :t“xr_..n-f-'E33 C} 1:2 1 _‘ ' \fi ' -.5 ran- ~ I ____.e'_ _ _ F- "I if I 1' I. .t «H;- JI: .. [I '-.' 'r. D 3 L ._ W“. (Jr. '- ' r—L‘F'ka .I-I' :- I—L— IN I II: .1 {é 3:3 l H.» _ f“ _ ,..- 5. Reeiatur R1 = 10 Q is; cunnected in series with twu t'cciatui's H2 it] Q and R3 = In if 51 connected in parallel. The ccmhiuaticn is connected acrcca a hattct'j.r with E = 5 V. the cun‘entut l‘ESlSlUl' R3152 ft a; __ El + i? .93 t “m 4 HERE—iii} :ti—gtzlfl Hue-1.51.. X ' i 7 ’ :3” I' E'EWELEZ'EE P" t r“ ._ ‘I/ _ A IE! ‘- 3 “j a.) I a __ m m t .- #2:“ in c c} 43.4 a ref; 9 e we a't ‘ refit 1.61:1 Illi_(|____1-'H‘A El [Ll A " t . ,e 3' J ~- = 7-; ii a: ct, tit i,___..r' a. An HM," circuit has a resistance R = liltltl fl, a capacitance cf C = {1.001 F, and an F” inductance L = Uflfll H. At what angular frequency ia the itupectauce cf Thifi circuit the smallest? I ____l___ i" 'i “i "3.6 A 5 .‘n: 113 Iatlfa \ -:-_ I f“ :: " f _ -,-. ‘—." 1'" " } (A: -dll_lll\5L||I:-J'_';F~] Ii B} l X It)2 Iaclfs C.) 5 x Ill?“ radii: I x rams 'J- —' II I .. if r', .n'-,.-'r-;_- '_, In: I‘I‘r _" q E} I a 1:114 mate [,4 t . . i { “Mi/d Page _t 7. A loop of 1tirire carrying a current of it} A is in the shape of a right triangle Iwith two J' {it equal sides. each 15 cm long. A (in? T unifortn magnetic field is anti-parallel to the hypotenuse. The resultant net magnetic force on the entire triangle has a magnitude of: F iéfrfivl as it}? _.. it Emil J; ' J- 4:" \a J B '3’, D N 1' r-- _. , r t E; Elm":- *' :2, ‘_ if“ Lil-Pi: i Jlab‘t = ii 'i_ 5;,” xi “ii-i. ’ “‘"r‘ i k | . +_.__;. f 1F—— -—3> r_ l-,I.. I , r.» Lia-L) ll d _{‘ \,_f | JP! {Ii I ’Ié-.. 'II It". B) U'ZIN F" Fab“? HI J".— !..,,1-t- .i‘ .Le-«H _ _ #5) '1. . ‘ r5}. . "-3 t3.) MUN : HE. - “a I I N : IF: “III-r4 i. -..*-'.r_ "II If .' ;_' .--I 11} MIN ,_ . .ii.-- - . o. i so Lem is fiero El. A particular resistor dissipates {15 W when conncctcd to a 3 if pfltfli‘ttifll difference. 6]) When connected to a l ‘U' potential difference. this resistor will dissipate: so as w "f’1_._.a‘§c.i o. —.- w ill 2 1 v r i. t. E) (1.113”? W t i,_ 'i. . i. _ ' “J: g) 1.5 w "rel/IE in ref—:— :2: -..‘ii._—:~;-. 1}” K ‘i ii .V 'n. (9}) onsaw l ‘r’. F; __ {J 1U] Irr', 'I F.) none of these ' r ‘3'ng * 9. r‘t long straight wire is in the plane of a rectangular conducting loop. The straight 1.irire ' initiallyr carries a constant current i in the dincction shown. 1|llfiliile the current i is being increased. the current in the rectangular loop is: .s , ‘ gig Lei-r r't tnLla m-‘u IZ- C-:.t*_'. [- f I .I' . . K K (K. LI. LT. 7f LL. 1" | -_ a" |'.-'- :'I '! I'r: L" II: ‘N-t J I I |.-. III. | I I: I I i. 1 -....--i.. ..1 1n ._.-" -' 1 £4 ’14. F1 i I - a II L I "--'-'-.' "I 5 r _ .Ji I . "If f6 11> cL-i t- t +: e J- ; J Jr l ZEI'U Illa: (13.35. x ._ If'rq :11 yr»! _-; .i ;-_r -|" . t'--'| ' I . I q. B} clockwise haw _ r. I- __ H r. j _. I._ M -" r . I - - -_ ._. _- 1 _ I. - H i—I- I. . -. (Fiji counterclockwise ~ i I, . : F 1 i- L | w I ! I. —. . . 5r- I- - -. ' 1. :_- ':it I D} altematcs between clockwise and counterclockmsc ,J' -. u . . . . ' “I. |_- . I 1:) cannot be determined Without ltuowrng the rate of increase in it Lc-o'f. ._ u I t l. “L .l in ":i'l i'" 3'- ' | .‘ii. ill”; L I': II A .J I ._;. .1 ' Jk its. i J suit“ I d Page cl lfl. Twu leng parallel etraighl wires pierce the plane ef the paper ii em apart? as ShD‘Wfl helew. 'l‘hey each carry 2 A intu the paper. The magnetic field at the pcint P half way,? _..a- ii. 3;. hetween twe wire-r. is {in '1'}: A ~ Exfizr t§éie F'le 110x TU—l‘ €3- :—:I." Nix—fir 4': j .3} Mix lfl 5 Iii]! ‘ Hep _5 .. C} 3.0 x It;1 S #71:" LI-I I_ II . I A I ,, t h} 411in l l“ - ‘ - - {Eififl .= i i.:~ir tlfitkeh vvtappqyy.nfiih 31; 1 E. 1' "TEL? : I'__j I Q I l . Radio waves el‘ wavelength Still in here a 1" requency cf: .2. _ A; — . . . .- i. I-'._1. -.--.r' 'h-‘V-l L" I .l'L'JE'fluf: _ I-F _' . H H __'__ ?\ sun kHz _ '- ' -‘~ ' :i'" i” } lMi—L: ' in aMHz : E] 1'03 kHz . . --r' ' ji-"l-a; 12. An iIILiLILJlGI' with inductance i”. and a reaiiiter with resistance R are wired in series re an L“ ideal hatter with end e. A switch in the circuit. is opened at time t: D. Immediately after the switch is. cleeerl the perential differences acreee the indecter and reaister: fit—l m “i E iii-"u = i - e' Lite} tat - {J "4i; .-. “if -. ri- LE}? are E“... U 1-:— - C] are eiE, hill 24;. it: _ 3:, _- ,t w -_ I J 1.1.... . _'__*,"_'. J; :-I_-_. .I..I : I; _ '_ tar, I D3] --I " L1 Li|'._|_ _.'.I:_ - I'll ' I_-.|.:l;- _ ' :: I.“ | ii} unknown since the rate el' change ef the current is net given j; 13. A ureter: {charge +e), traveling perpendicular In a magnetic field. experiences the saute force a trip] y—ieuizee ice at carhen {charge +3e'} which is alae traveling perpendicular Le the saute field. The ratie of their speeds, rpmtfivwm is: is.) are if I 17-- . _ _ _. r; i- . i. B} 1 "I'll"'1 P" f-'-' 1*‘“"-"' F' hula-9' r. - - .'-.. I It: Lieu-"Ill " L12. 2 ' 3 _- :3} _ r___ _ I.. n a. g - J II-ILI... . :__, -' "I I . - al' 'I. '. "I f 'iJlr. .-."-.._. '. llJl-I 1.:- rl__..,. I- imgefi j 14. Ali electromagnetic wave is transporting energy in the positive 1:: direction. At one point 453‘ and one instant the magnetic field is in the negative. 1' Eiil'xCCtiflfl. The electric field at that point and the same time is: F : Ej‘ sit; q .. ~_ a '. 'H' ates- of: P'Fflrflqifltt on m} positlvoy direction is“ I I _ I J '35 negative}? direction ': Lie-e N (1th It" “W” " 'f' L'Jc 4' o 2.1.— v“ i__._ ‘7 .. - st_ C} positiie z flotation J}____.}E 1! “L h r fl -_ in”. J I I3, I. t: I. W. LT D} negative 1’. direction “If/1 I__ '--"" ' bl} negativexdirection #/ f" . J“ 9. - -. . . .« "'I :x :-.".’“|\- 15. Each of the [our capacitors shown has a capacitance of 5th} #F. The voltmeter reads “.I'UUUV. The magnitude of the charge, in coulotnhs, on each Capacitor plate is: F “hit-Jill: _r. $1 II -._-x IE" - a. .I‘ I;'- u. I, ' flatten :I'i-Z'..J.."'-' "-F '.'.'_ H/t- J'-"JGt.l-‘" ‘3 'L'». F i' I'II". ix Jars-H '-' ' _'I ."'I".-'- "" i' :Jr'f' | PH" I. III {R '| Le rt 1. t w; -t- --.~. r -} f3; .14.}. a/ fit (12 .; -I - i.“ ' .;__'_a’;: as fl _ (.1 I C} 2F] 'e ' it -' .1 a P; \I D) 50 : r; .v: .u i s, o v i 15.} none of these lti. Four long straight parallel wires are placed in 4 corners of a square. The wires carry equai currents into or out of the page as shown in the figure below. The direction of the- net magnetic force exerted on wire F is: It] I "I - . | -.-. -' I. I) III r 1_ I:- ____.._ L _._ . .I. |I-.Ji. I I' J .- r" —fi ‘6' 3| RQZTF'J” Th2 —.—-~—-s -.... a" Ir J o r». .I '- '1 I L -. . I \III ,I g In" :2.“ :51 E .I‘II _. I. I .IPZII _ :3 __:-\. is 'T PEI.I . ' I __.. I n I. 1' rl "t |‘.t:"i E1: L i- n +' ._--- .-'— A} zuo 7i r t 4 it , west " ’ C)“ cast TJ} north E} south Page 4‘: ...
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Exam2_59955_sol - .» q; "- l. A hollow...

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