# CDMA - The following picture is a copy of a Figure in the...

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The following picture is a copy of a Figure in the textbook. It shows a CDMA example that supports two senders. Suppose that the receiver wanted to receive the data being sent by sender 2. Show (by calculation) that the receiver is indeed able to recover sender 2’s data from the aggregate channel signal by using sender 2’s code. To calculate the data of sender 2 received by receiver exactly we have some calculation formula. Since, ……… equation (1) Where Z i , m is the Output of the CDMA encoder representing i th data bit d i of m th mini slots send by sender ‘s’. ‘i’ represents slot number, ‘m’ represents number of slots, ‘d i ‘ represents data bit for that particular slot ‘c m ‘ represents code digit of particular mini slot ‘s’ represents sender.

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Now calculating for s=1, i=1, m=1….8, and = -1 = (-1) * (1) = -1 = ( -1 ) * ( 1 ) = -1 = ( -1 ) * ( 1 ) = -1 = ( -1 ) * ( -1 ) = 1 = ( -1 ) * ( 1 ) = -1 = ( -1 ) * ( -1 ) = 1 = ( -1 ) * ( -1) = 1 = ( -1 ) * ( -1 ) = 1 -1 , -1 , -1 , 1 , -1 , 1 , 1 , 1 = For s = 1 , i = 0 , m = 1…….8 , and = 1 = ( 1 ) * ( 1 ) = 1 = ( 1 ) * ( 1 ) = 1 = ( 1 ) * ( 1 ) = 1 = ( 1 ) * ( -1 ) = -1
= ( 1 ) * ( 1 ) = 1 = ( 1 ) * ( -1 ) = - 1 = ( 1 ) * ( -1 ) = -1 = ( 1 ) * ( -1 ) = -1 1 , 1 , 1 , -1 , 1 , -1 , -1 , -1 = Similarly doing the same for s = 2 , i = 1 and , m = 1…….. 8 and

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