# tarea 2 - Una persona de 70 kg de masa coloca una báscula...

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Unformatted text preview: Una persona de 70 kg de masa coloca una báscula dentro de un elevador y se sube en ella, ya en m Determina la aceleración del elevador y si este se mueve para arriba o para abajo, acelerando o fr Movimiento #1 (66 kg) m= 66 kg Movimiento #2 (74 kg) M=74kg Movimiento #3 (70kg) elevador hacia abajo s= 7.81 m/s2 f= ? F= m.g F= (16seg)(98)m/s2 F= 647.46 N A= F= > 647.46N/70 kg A=9.24 m/s A= 9.24-9.81=.56m/s2 F=? F=m.g F=(74kg)(9.81m/s2) F=925.94N A= f/m = 725-94N/70 kg = 10.37 m/s2 A=10.37m/s2-9.81m/s2=-.56m/s2 M= 70kg s=9.51 m/s2 f=? F=m.s F=(70kg)(9.81m/s2) F=1636.90N hacia arriba A=f/m = 6.3670/70kg= 9.81 m A=9.81m/s2 = 9.81m/s2 A=0 m/s2 Estado estatico A=vf-vi/t =16/6 =2.66m/s2 vi+c=a=O A=vf-vi/t=O-16/45s=-4m/s2 y se sube en ella, ya en movimiento, observa distintos valores de la lectura de la báscula. ra abajo, acelerando o frenando, cuando los valores de la báscula son: Movimiento #3 (70kg) levador hacia abajo =9.51 m/s2 =(70kg)(9.81m/s2) =1636.90N =f/m = 6.3670/70kg= 9.81 m/s2 =9.81m/s2 = 9.81m/s2 =0 m/s2 Estado estatico =vf-vi/t =16/6 =2.66m/s2 =vf-vi/t=O-16/45s=-4m/s2 ...
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