Statistics Quiz 1

# Statistics Quiz 1 - Quiz 1 1 9.14 8.14 8.74 8.77 9.26 8.10...

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Quiz 1 1.) 9.14+8.14+8.74+8.77+9.26+8.10+6.13+3.10+9.13+7.26+4.74/11=mean; mean = 7.5; (9.14-7.5)^2+(8.14-7.5)^2+(8.74-7.5)^2+(8.77-7.5)^2+(9.26-7.5)^2+(8.10-7.5)^2+(6.13-7.5)^2+(3.10- 7.5)^2+(9.13-7.5)^2+(7.26-7.5)^2+(4.74-7.5)^2/11=standard deviation 1.64^2+0.64^2+1.24^2+1.27^2+1.76^2+0.6^2+(-1.37)^2+(-4.4)^2+1.63^2+(-0.24)^2+(- 2.76)^2/11=standard deviation 2.69+0.41+1.54+1.61+3.10+0.36+1.88+19.36+2.66+0.06+7.62/11=standard deviation 41.29/11=3.75=standard deviation The mean of this data set tells us that the average time that a consumer must wait on hold before talking to a customer service representative is 7.5 minutes. The standard deviation of this information tell us that the numbers are pretty close together and are not spread to far apart from each other. This means that most of the time the consumers are on hold waiting to talk to a customer service representative is
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