Unformatted text preview: hydroxyl functional group is sp 2 hybridized. In both compounds the oxygen compound is sp hybridized, but in camphor there is a pi bond that contributes to the hybridization state. 2. A NMR can be used to provide evidence that camphor was formed because there was a hydroxyl group and an alkyl hydrogen located alpha to the carbon atom (from question #1 above). In the camphor product there is a ketone functional group attached to the same carbon. The hydroxyl group produces a broader peak than the ketone group, and also there is no peak for the non-existent alkyl hydrogen in the camphor sample that was present in isoborneol sample. 3. If no “cold finger” was used in the sublimation apparatus, then condensation would not have occurred because there was no source of lower temperature. Thus, no purified camphor product would have formed on the cold finger and melting point determination would not have been possible....
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This note was uploaded on 09/16/2008 for the course CHEM 262L taught by Professor Mbadugua during the Spring '08 term at UNC.
- Spring '08