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Unformatted text preview: (Moles zinc/moles iodine)= (.0028mol/.0078mol)=(1/3) Here is the equation from 7-1 rewritten with the appropriate numbers in place of the variables: ___________________________________________________ Results Weight of zinc used:0.502g Weight of iodine used:0.498g Dry weight of unreacted zinc remaining at the end of experiment:0.321g Dry weight of anhydrous zinc iodide:0.021g Moles of iodine reacted:0.0078moles Moles of zinc reacted: 0.0028moles Calculated ratio of zinc to iodine: 1:3 Proposed equation for the formation of zinc iodide based on my experimental results: ZnI +3I Zn + 3I ZnI3 Experimental moles of ZnI2 obtained: 6.58X10^-5 moles Theoretical Moles of ZnI2 based on moles of Iodine reacted: 6.58X10^-5 moles Theoretical moles of ZnI2 based on the moles of zinc reacted: 4.71X10^-5 moles Percent yield: 71.58% yield...
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- Spring '08