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Unformatted text preview: (Moles zinc/moles iodine)= (.0028mol/.0078mol)=(1/3) Here is the equation from 7-1 rewritten with the appropriate numbers in place of the variables: ___________________________________________________ Results Ÿ Weight of zinc used:0.502g Ÿ Weight of iodine used:0.498g Ÿ Dry weight of unreacted zinc remaining at the end of experiment:0.321g Ÿ Dry weight of anhydrous zinc iodide:0.021g Ÿ Moles of iodine reacted:0.0078moles Ÿ Moles of zinc reacted: 0.0028moles Ÿ Calculated ratio of zinc to iodine: 1:3 Ÿ Proposed equation for the formation of zinc iodide based on my experimental results: ZnI +3I à Zn + 3I à ZnI3 Ÿ Experimental moles of ZnI2 obtained: 6.58X10^-5 moles Ÿ Theoretical Moles of ZnI2 based on moles of Iodine reacted: 6.58X10^-5 moles Ÿ Theoretical moles of ZnI2 based on the moles of zinc reacted: 4.71X10^-5 moles Ÿ Percent yield: 71.58% yield...
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This note was uploaded on 09/17/2008 for the course CHEM 01 taught by Professor Keller during the Spring '08 term at Arizona.
- Spring '08