# Doc1 - that the mixture with the highest percent of OJ...

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F = Cups of OJ flavor - measured in cups W = Cups of Water - measured in cups T = Total number of Cups in the mixture - measured in cups Mixture A tastes more “orangey.” I naturally approached this problem using a constant ratio. F (Cups of OJ flavor) as related to T (Total number of cups in the mixture) (F/T)100 = the percent of the mixture that is OJ. I choose this approach over the other approaches because I was dealing with different size mixtures in terms of the total number of cups in the mixture and figured
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Unformatted text preview: that the mixture with the highest percent of OJ tastes the most “orangey.” Mixture B Scenario 1 T = 8 cups F = 16/3 cups of OJ flavor W = 8/3 cups of Water Mixture B Scenario 2 T = 9 cups F = 6 cups of OJ flavor W = 3 cups of Water Mixture B Scenario 3 T = 7.5 cups F = 5 cups of OJ flavor W = 2.5 cups of Water These scenarios would yield the same flavor as mixture A because each...
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