Quiz 1

Quiz 1 - I+.05 method: (i-0.5)n*100=k for kth %ile. Returns...

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I+.05 method: ( - . ) * = i 0 5 n 100 k for kth %ile. Returns item place in array of ordered set. K as integer. N+1 method: + = kn 1 i . K in decimal form. For interpolators (e.g. 3.5), ipart + fpart(larger-smaller). Sample mean is just average Sample variance = = ( - ) - s2 i 1n xi x 2n 1 PDFs (Probability Distribution Functions): P(a<x<b) = abfxdx 1) F(x) >= 0 i.e. = fx kx2 < < , for 0 x 2 0 elsewhere 2) -∞∞ ( ) f x = 1 3) CDF (Cumulative Distribution Functions): 4) F(x) = P(X<x) = -∞ xfudu . Shows amount of probability to that point. 5) f(x) = some PDF 6) µ=E[x]= -∞∞ xfxdx 7) = =-∞∞( - ) = -∞∞ - σ2 Vx x μ 2fxdx x2fxdx μ2 8) Normal Distribution: 9) X:n(µ, σ 2 ) -> = - Z x μσ 10) P(Z>z)=P(Z<-z) 11) 12) PMFs (Probability Mass Functions): 1) F(x) >= 0 for all x 2) ( ) f x =1 3) = = ( ) μ Ex xf x 4) = = - σ2 VX Ex2 μ2 5) = ≤ =-∞ = < , = F PX x xfx Fx 0 for x 1 Fx 18 for ≤ ≤ , . 1 x 3 etc 6) Binomial distribution (discrete): 7) Deals with some # of trials with one of two outcomes
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This note was uploaded on 09/17/2008 for the course IEE 380 taught by Professor Anderson-rowland during the Spring '06 term at ASU.

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Quiz 1 - I+.05 method: (i-0.5)n*100=k for kth %ile. Returns...

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