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Unformatted text preview: center will be midway between two nodes, and there will be an antinode at that point. c) The sixth harmonic will have only 7 nodes on the same string. Therefore, the distance between nodes will be greater, and the wavelength will be longer . d) Since the wavelength is longer, the frequency will be lower , since f = v / . Q16.10. Only in case (d) is it possible that the two strings oscillate at the same frequency. Since the tension is higher in string B , while the densities are the same, the wave speed is higher in string B than in string A . Therefore, waves in string B would have longer wavelengths than waves of the same frequency in string A . Case (d) is the only one to satisfy that condition....
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- Spring '06