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# hw02 - PHYS-1200 PHYSICS II SPRING 2005 HOMEWORK SOLUTIONS...

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Unformatted text preview: PHYS-1200 PHYSICS II SPRING 2005 HOMEWORK SOLUTIONS CLASS 2. 21.08, 22.73, 24.09, 24.28; Q23.03, Q23.08, Q23.10 21.08. a) The forces on Q due to q 1 and q 2 must be directed opposite to each other if they are to add to zero. Q is between q 1 and q 2 , so q 1 and q 2 will produce forces on Q that are in opposite directions if they are of the same sign. Therefore, they must be of the same sign, whether positive or negative. The distance between q 1 and Q is a + a /2 = 1.5 a . Then the magnitude of the force produced by q 1 is: 2 1 1 ) 5 . 1 ( 4 1 a Q q F πε = The distance between q 2 and Q is a – a /2 = 0.5 a , so the magnitude of the force produced by q 2 is: 2 2 2 ) 5 . ( 4 1 a Q q F πε = . Since these forces are in opposite directions, their magnitudes must be equal to produce a force of zero. Then: 2 2 2 1 ) 5 . ( 4 1 ) 5 . 1 ( 4 1 a Q q a Q q πε πε = , or 2 2 2 1 ) 5 . ( ) 5 . 1 ( q q = , so 2 2 2 2 2 1 9 3 5 . 5 . 1 q q q q = = = 9 2 1 = q q b) Since Q is not between q 1 and q 2 they must be of opposite signs if the forces they produce are to point in opposite directions. Again, the magnitudes of the forces produced by the two charges must be equal. Now, the distance between q 1 and Q is...
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hw02 - PHYS-1200 PHYSICS II SPRING 2005 HOMEWORK SOLUTIONS...

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