hw17 - PHYS-1200 PHYSICS II HOMEWORK SOLUTIONS CLASS 17....

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PHYS-1200 PHYSICS II SPRING 2005 HOMEWORK SOLUTIONS CLASS 17. 17.46, 17.54, 17.64, 17.84 17.46. Since the violin string is too tight, the tension is too high. That means that the wave velocity in the string is higher than it should be, and the frequency is higher than it should be. Four beats per second are heard, which means that the frequency difference between the tuning fork and the violin string is four hertz. The frequency of the violin string is four hertz higher than the tuning fork or f = 440 Hz + 4 Hz =444 Hz. Then the period is: Hz f T 444 1 1 = = T = 2.25 ×10 -3 s 17.54. Call the speed of the French submarine v F , and that of the U.S. submarine v U . a) In this part of the problem, the French submarine is the source and the U.S. submarine is the detector. Since they are moving toward each other, the detected frequency is given by, km/h 0 . 50 km/h 5470 km/h 0 . 70 km/h 5470 Hz) 1000 ( ' - + = - + = - + = F U S D v v v v f v v v v f f f = 1020 Hz = 1.02 kHz b) In this part of the problem, the U.S. submarine is the source and the French submarine
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hw17 - PHYS-1200 PHYSICS II HOMEWORK SOLUTIONS CLASS 17....

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