samp22 - = = mK h p h = 5.25 10-15 m = 5.3 fm b) Since =...

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SAMPLE PROBLEM (Class 22) ANS: a) p h = λ . To solve this, p is needed, and kinetic energy is given. m p m v m mv K 2 2 2 2 2 1 2 2 1 = = = . Then, mK p 2 2 = , and mK p 2 = . J/eV) 10 eV)(1.6 10 kg/u)(7.5 10 u)(1.66 2(4.00 s J 10 63 . 6 2 19 6 27 34 - - - × × × × =
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Unformatted text preview: = = mK h p h = 5.25 10-15 m = 5.3 fm b) Since = 5.3 fm << 30 fm it is a good approximation to neglect the wave nature of the particles....
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This note was uploaded on 09/17/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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