samp03 - SAMPLE PROBLEM a) The charge is the same on each...

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Unformatted text preview: SAMPLE PROBLEM a) The charge is the same on each capacitor, and the capacitance of the series combination is, CC (2.0 F)(8.0 F) Cs = 2 8 = = 16 F . C2 + C8 2.0 F + 8.0 F Then, Q2s = Q8s = CsV = (1.6 10-6 F)(300 V) Q2s = Q8s = 4.8 10-4 C = 0.48 mC -4 Q 4.8 10 C V2 = 2 s = V2 = 240 V C2 2.0 10 -6 F Q8 s 4.8 10 -4 C = V8 = 60 V C8 8.0 10 -6 F Notice that the sum of the two potential differences adds up to the applied potential difference of 300 V. V8 = b) When re-connected in parallel, the capacitance of the combination is, Cp = C2 + C8 = 2.0 F + 8.0 F = 10.0 F The charge on the combination is Qp = Q2 + Q8 = 9.6 10-4 C Q p 9.6 10 -4 C Then, the voltage, V2 p = V8 p = = V2 p = V8 p = 96 V Cp 10 10 -6 F The charge of each capacitor is now Q2p = C2V2p = (2.0 10-6 F)(96 V) Q2p = 1.9 10-4 C = 0.19 mC -6 Q8p = C8V8p = (8.0 10 F)(96 V) Q8p = 7.7 10-4 C = 0.77 mC c) Q = 0, so V = 0. ...
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This note was uploaded on 09/17/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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