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Unformatted text preview: Since the fuse can handle 15 A, the number allowed is, N = (15 A)/(4.17 A) = 3.60. Since a fraction of a lamp is not possible, the answer is, N = 3 lamps...
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This note was uploaded on 09/17/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
- Spring '06