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Unformatted text preview: Do NOT write on these sheets or take them with you! The next class needs them too! PHYS-1200 PHYSICS II SPRING 2005 Class 19 Activity: Interference of Light Waves SOLUTION 1. The sketch shows two light rays that are initially in phase and reflect from several glass surfaces. Neglect the slight slant in the path of the light in the arrangement on the right. a) What is the path length difference of the rays in terms of d ? 2 d b) What should that path length difference equal, in terms of , if the rays are to be exactly out of phase when they emerge? 2 d = ( m + ) c) What is the smallest value of d , in terms of , that will allow that final phase difference? m = 0, so d = /4 2. The sketch shows two parallel waves of light, initially in phase. One passes through a piece of glass, of index of refraction n = 1.30 and length L = 9.00 m, while the other travels the entire path through air. a) Suppose the wavelength of the light in air is = 450 nm. In wavelengths, what is the phase difference between the two waves after the lower one emerges from the glass? In the path of length L , for the wave that goes through air, the number of wavelengths is: L N = . For the wave that goes through glass, the number of wavelengths is: L n n L N n = = / The difference is: 6 m 10 450 m 10 00 . 9 ) . 1 3 . 1 ( ) 1 ( 9- 6 = - =- =- =- = - L n L L n N N N n In radians,...
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- Spring '06