MT1L1 - Midterm 1, Physics 7A, Fall 2006 1 Problem 1: a) [7...

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Unformatted text preview: Midterm 1, Physics 7A, Fall 2006 1 Problem 1: a) [7 pts total] 52m 250m 36 o y x v Ocean [1 pt] Draw the trajectory picture and define the coordinates system as in the above picture. Note: you can use other coordinates system, make sure you use a unique system through your solution. [1 pt] Then the initial conditions are x = 0(m) , y = 52(m) v x = 48(m / s) cos(36 ) 38 . 83(m / s) , v y = 48(m / s) sin(36 ) 28 . 21(m / s) We also know accelerations in both horizontal and vertical directions a x = 0(m / s 2 ) , a y =- g =- 9 . 8(m / s 2 ) [2 pts for part b) Method I] Then we can write down the kinematics equation for velocity v x ( t ) = v x 38 . 83(m / s) , v y ( t ) = v y- gt 28 . 21(m / s)- 9 . 8(m / s 2 ) t [3 pts] and position x ( t ) = x + v x t 38 . 83(m / s) t y ( t ) = y + v y t- (1 / 2) gt 2 52(m) + 28 . 21(m / s) t- 4 . 9(m / s 2 ) t 2 ( to be continued ) b) Method I: [7 pts total] [2 pts] When the golf ball is at the maximal height, its vertical velocity must be zero.When the golf ball is at the maximal height, its vertical velocity must be zero....
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This note was uploaded on 09/10/2008 for the course PHYSICS 7A taught by Professor Lanzara during the Fall '08 term at University of California, Berkeley.

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MT1L1 - Midterm 1, Physics 7A, Fall 2006 1 Problem 1: a) [7...

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