{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

exam2_A - EON317 Midterm Examination#2 Form A Professor...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
EON317 Midterm Examination #2 Form A Professor Manochehr Rashidian March 13, 2008 1. (40 POINTS) a. (15 points) Let μ denote the average speed over the strech. Then the null and the alternative hypotheses are H 0 : μ = 70 , H a : μ > 70 . Based on the data set, n = 8, ¯ x = 75 . 3750, s = 6 . 4351 and the test statistic t = 75 . 3750 - 70 6 . 4351 / 8 = 2 . 3625 . Since t . 100 = 1 . 415 < t = 2 . 3625, we REJECT the null hypothesis, H 0 . Therefore, we conclude that the average speed of traveling over a particular strectch of a highway exceeds the legal limit of 70 MPH at 10% significance level. b. (10 points) Drawing upon the t -distribution table, we can infer that . 025 < p - value < . 050 since 1 . 895 = t . 050 < t < t . 025 = 2 . 365. So the null hypothesis will be rejected at significance level α = . 05 but cannot be rejected at α = . 025. c. (5 points) We need to assume that each sample is from a underlying common (approximately) normal distribution. d. (10 points) A 90% confidence interval is ¯ x ± t α/ 2 s n = 75 . 3750 ± 1 . 895 6 . 4351 8 1
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
= 75 . 3750 ± 1 . 895 × 2 . 2752 = 75 . 3750 ± 4 . 3115 , which is [71 . 06 , 79 . 69]. We are 90% confident that the average speed of traveling over a particular stretch of highway lies between 76.1 MPH and 79.7 MPH. So we have 90% confidence that the average speed exceeds 70 MPH.
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern