notecard 2 - Linear quantities Force F Mass(inertia m...

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Unformatted text preview: Linear quantities Force: F Mass (inertia): m Newton's 2nd Law: Fnet = ma Work: W = F||d Power: P = Fv Kinetic Energy: K = mv2 Work-energy Theorem: Wnet = mv2 - mv02 Linear Momentum: p = mv Kinetic Energy: K = p2/2m Rotational Quantities Torque: | | = rF = rFsin Moment of Inertia: I = 1/2mr^2 Newton's 2nd law: = I Work: W = Power: P = Kinetic energy: K = I2 Work-energy theorem: Wnet = I 2 - I 02 Angular momentum: p = Kinetic energy: K = p2/2I Example 8.12: A student opens a door: Given: mdoor = 12.0kg; F = 40.0N;r = 0.90m; hdoor = 2.0m; wdoor = 1.0m Find: From figure 8.20(k); I = mL2/3 = 4.0 kgm2 = rF = 36 nm = /I = 9.0 rad/s2 Linear forms v = v0 + at x = x0 + (v+v0)t x = x0 + v0t + at2 v2 = v02 +2a(x-x0) p = mv F = ma = p/t U = mgh K = mv2 Angular Equivilents + = t = 0 + +(0) t = 0 + 0t + t2 2 = 02 +2-( 0) L = = rFsin() = I = L/t K = I 2 ...
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This note was uploaded on 09/15/2008 for the course PHYS 1401 taught by Professor Broyles during the Summer '08 term at Collin College.

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