It is especially clear for the case of a b when a

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Unformatted text preview: l to the plane acting on one of the positive charges is a sum 1 a F = ke q 2 2 - 2 . (10) a (a + 4b2 )3/2 The first term in (10) is the force from the other positive charge, while the second term is from the negative image charge of the other positive charge. (Its own image charge produces the image force component only perpendicular to the plane.) In the case of a b, (10) reduces to 6ke q 2 b2 ke q 2 F = Fc = 2 . (11) a4 a Eq. (11) can also be directly obtained from the field of the dipole pair (charge)-(image charge). 3...
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This note was uploaded on 09/18/2008 for the course PHYS 2326 taught by Professor Ingor during the Spring '08 term at University of Texas at Dallas, Richardson.

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