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Unformatted text preview: Exam lll — April 2, 2003
Chem (PfOf. Baer (Please primmurnamc) Useful and essential information:
ATHO[H30(V)] : —241.8 kJ/m AfH°[HgO(E)] = 285.8 kJ/m Af‘HO[HQO(S)] = 293.8 kJ/m R : 0.082 L—At/mK = 8.314 J/mK P : RT/(Vb) — a/v2 PV = RT[1 + (b — a/RTW“ + (b/V)2 ...]
w : Pe\dV w : nRTan3/Vl AU = q + w AH = AU + APV Cp a CV : T(5P/6T)y(6V/6T)p
oc=V'l (av/5m KT : —V" (aV/ap)T a : [8T/6P]H = [T(6V/5T)p —V]cp'1 [T3,»"r1]c‘“R = WV2 m = (5&th = nap/em — P (aH/ap)r = T(aV/ar)p * V Chain Rule for XYZ: (_€X/6Y)Z(5Y/6Z)x(8Z/6X)y = l dU = TdS — PdV dH = TdS + VdP dA = SdT — PdV dG : SdT + VdP (er/"ems = tap/ask (er/5mg = (av/63),) (aP/am = (ES/Mn (av/5m : —(ES/€P)T (56:‘5P)T : v (go/am = —s [€(AG/T) em = —AH/r2 [aAG/T) / 5(1/T)]p : AH AGHM = nRT(xx\lnxs\ + xBlan) AG, = RTanCq dan/dT = AHro/RT2 dan/"d(l/T) = AHr0/R
dP"dT = As(,_9g,,~"A\/'UAB = AH/TAV d1nP/d(1/T) = ~AmpH/R Vm = (aV/emmm it = p“ + RTlnP HA = a; + RTln(PA/PA*) = u; 1* RTln(xA) nAduA + anuB : 0 P8 = XBKB AT = KmB HVm = XRT Show your work. No credit without it.
1p. ('1 8 pts) The vapor pressure in mmHg ofa liquid can be represented by the equation:
lnP = 8.750 — 1625T'1. Calculate the enthalpy of vaporization. the normal boiling point. and the standard entropy of vaporization at the normal boiling point. 0 _ Z I _,
All/ml : __[éZS—:—éjj’_zaf BHV: IBISk4 AMPH [551(J
Ox R Tboiling: l< L. Amps": [£6 [/< 2 2p. (14 pts) What is the freezing point of ice under 20 atm (pressure exerted by a car), given the molar
volume of water as 0.0180 L/mole, and ice as 0.0195 L/mole? Use information on page 1. £2 E' éﬁ A?:4€20~l:[email protected]
2 A __ v
dl (A T ans
80?: givgoll’ Av = 0120  0mg =
(“A AV ~ 100mg L
A? : iii A!” M = Amm MW
TMAV ~ ~25}: » (ZﬁSXl
 k3“
? IMAV , <$.00
AT: A/ 23000T27?2L_:1+
AH ‘ Wk 3p. (13pts) What is the molecular weight of a protein if the osmotic pressure if 25.5 mmHg when 2.75
g of the sample is dissolved in 50.0 g of water at 298 K? 'WV=xRT
35—5 . L. f
X: ﬁg: <w>: 2‘47X/0ﬂ; MfeﬂddjSO/‘ZJ‘e
(022)0242) 7w "(o/U? Solve” AM 50.03 : 2,7:{8mr9ﬁaaﬁllmo 1+
wakme. L2.‘+¥xlo‘§)(2.7'%8ua€ajc (9,2(9 26/0 “Arena 4p. (15 pts) What is the chemical potential of the following species: (9’ = 2&3
CW"
ap. H2(g) at a pressure of 0.5 atmf
_ 0+27¢QAOSI l."7‘l<~3 I Bp. H20([) pure (use info from page 1) *‘~ ’.  2%52 Cp. H20(£) in an ideal mixture Where X(H20) = 0.50 5p. (13 pts) What is the vapor pressure of H20 at 100°C when 5.0 moles of ethylene glycol is added to 95 moles of water?
'P = ?° 7con : Qcci'w)<.QS> : 0.951% b) 6p. (12 pts) What is the partial molar volume of MgSO4 when m(MgSO4) = 0.050 mol/kg given that the total volume is found to be:
V(cm3) = 1001.21 + 34.69(m0.070)2 : “maﬁa/91°) 346?
r , 183% MZA 0.l"im +"' 2m 391' 'zw'o} 3U /———~ am 7p. (15 pts) Find the standard reaction free energy, enthalpy and entropy at 400 K if the equilibrium
constant for a reaction is found to be: K(300K) = 3.5)(10‘4 and K(400K) = 8.8x10’4. L KL  AH fl _ J.
12‘ ° :12" “v 3‘”
0.92.2 :— ‘Eﬁl 1514:9214?
[2
AS ' Ala/1M” ~_ —7>§.3’3/1< I have neither given nor received aid on this exam Please sign 27 ...
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This note was uploaded on 09/19/2008 for the course CHEM 181 taught by Professor Baer during the Spring '08 term at UCSD.
 Spring '08
 BAER

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