CH302%20Quiz%202%20Answer%20Key%20sp08

CH302%20Quiz%202%20Answer%20Key%20sp08 - 1 CH302 Quiz 2...

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1 CH302 Quiz 2 Answer Key Spring 2008 Q# 1. (10 pts.) Consider the following chemical equation: 2 N 2 O (g) 2 N 2 (g) + O 2 (g) If 10.0 moles of N 2 O are placed in a 2.00 L container at some temperature and at equilibrium it is determined that 2.20 moles of N 2 O remain, what is the Kc for the reaction? a) 50.3 b) 24.5 c) 19.6 d) 70.8 Answer: 22 2 2 N O (g) 10.0 0 0 7.80 7.80 3.90 2.20 7.80 3.90 2.20 7.80 3.90 [ ] 1.10 ; [ ] 3.90 ; [ ] 1.95 2.00 2.00 2.00 gg initial mol change mol mol mol equilibrium mol mol mol mol mol mol NO M N M O LL L 2 → 2 Ν ( ) + Ο ( ) ← −+ + == = = = 2 [ ] [ ] (3.90) (1.95) 24.5 [ ] (1.10) c M K = Q #2. (10 pts.) Kc = 19.9 for the reaction Cl 2 (g) + F 2 (g) 2ClF (g) What will happen in a reaction mixture that contains: [Cl 2 ] = 0.40M [F 2 ] = 0.20M [ClF] = 7.3M a) Qc = Kc, the reaction has established equilibrium b) Qc > Kc, the reaction is reactant favored and will shift to the left. c) Qc < Kc, the reaction is product favored and will shift to the right. Answer: c 2 2 K 700 ] F ][ Cl [ ] ClF [ Q > = = , therefore; the reaction is reactant favored and will shift to the left.
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This note was uploaded on 09/20/2008 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.

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CH302%20Quiz%202%20Answer%20Key%20sp08 - 1 CH302 Quiz 2...

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