08664 pc ac rtc 2 042747 1 m1 tr pc 2 m

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ) 2 m = 0.48 + 1.574 - 0.176 2 Peng-Robinson EOS aT p+ (VM - b ) = RT VM (VM + b ) + b(VM - b ) aT = ac RTc b = 0.0778 pc ac ( RTc ) 2 = 0.45724 = 1 + m(1 - Tr ) ( pc ) 2 m = 0.37464 +1.54226 -0.269922 Mixing rules for SRK and PR ...and it gets worse! How do you deal with a j multiple component mixture? aT = yi y j aTij i j ij are binary interaction coefficients values aTij = 1 - ij aTi aTj have to be given for each pair b = y jb j ( ) SRK example yi C1 0.65 VM=1.2 cu ft/lb mol Calculate pressure if T=709.6R Tc 342.9 Pc 666.4 bj 0.4784 acj 8687 acentric factor 0.0104 mj 0.4964 j 0.612 aTj 5317 C2 0.25 549.5 706.5 0.7232 21042 0.0979 0.6324 0.8349 17569 nC4 0.10 765.2 550.6 1.2922 52358 0.1995 0.787 1.0591 55453 b=0.6210, (use .02 bic C1&C4, .01 C2 and C4, 0 C1 and C2) aT=10773 p=8223 psia...
View Full Document

Ask a homework question - tutors are online