06) More Gas Laws 9_20

# 08664 pc ac rtc 2 042747 1 m1 tr pc 2 m

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Unformatted text preview: ) 2 m = 0.48 + 1.574 - 0.176 2 Peng-Robinson EOS aT p+ (VM - b ) = RT VM (VM + b ) + b(VM - b ) aT = ac RTc b = 0.0778 pc ac ( RTc ) 2 = 0.45724 = 1 + m(1 - Tr ) ( pc ) 2 m = 0.37464 +1.54226 -0.269922 Mixing rules for SRK and PR ...and it gets worse! How do you deal with a j multiple component mixture? aT = yi y j aTij i j ij are binary interaction coefficients values aTij = 1 - ij aTi aTj have to be given for each pair b = y jb j ( ) SRK example yi C1 0.65 VM=1.2 cu ft/lb mol Calculate pressure if T=709.6R Tc 342.9 Pc 666.4 bj 0.4784 acj 8687 acentric factor 0.0104 mj 0.4964 j 0.612 aTj 5317 C2 0.25 549.5 706.5 0.7232 21042 0.0979 0.6324 0.8349 17569 nC4 0.10 765.2 550.6 1.2922 52358 0.1995 0.787 1.0591 55453 b=0.6210, (use .02 bic C1&C4, .01 C2 and C4, 0 C1 and C2) aT=10773 p=8223 psia...
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## This note was uploaded on 09/21/2008 for the course PTEC 502 taught by Professor Sue during the Spring '08 term at University of Texas Medical Branch at Galveston.

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