neurohw1 - Question 1: a. Cm = cm * A Cm = .03 mm^2...

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Question 1: a. Cm = cm * A Cm = .03 mm^2 *5nF/mm^2 = .015nF b. Rm = rm * a Rm = 2M(Ohm)mm^2 / .03mm^2 = 66.6 M(Ohm) c. Tau m = Rm * Cm Tau m = 66.6 M(Ohm) * .015nF = .0999 m(Ohm)F d. Vss = Vm + Iapp/Rm -60mV = -70mV + Iapp * 66.6 M(Ohm) Iapp =1.5mA e. Vm(t) = Vss + (Vm(0) – Vss)e^(-time/tau m) -62mV = -60mV +(-70mV + 60mV)e^(-time/(.0999m(Ohm)F)) Time = 8.508 * 10^-4 s Question 2: clear  all ; dt = .0001; Rm = 10; taum = 10;           %tau m Time=200;            %simulation time t=0:dt:Time;         %make time array, in steps dt for time of  simulation E = -70;             %resting voltage v = zeros(size(t)); I = zeros(size(t)); refrakcount = 0;     %refrakcount, the counter variable refrakflag = 0;      % refrakflag, if at 1 then in refractory period  else proceded as normal tref = 3;            % tref, number of time steps for refractory period vthresh = -60;       %vthresh, threshold voltage vreset = -80;       
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This note was uploaded on 09/21/2008 for the course NBIO 136 taught by Professor Miller during the Spring '06 term at Brandeis.

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neurohw1 - Question 1: a. Cm = cm * A Cm = .03 mm^2...

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