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Practice Questions 7 Answers 1. D 2. A 3. B 4. C 5. A 6. C 7. B 8. B 9. ( 29 ( 29 2 2 2 / 2 0.5 1.96 0.5 32.67 1067.33 1068 0.03 z n ME α = = = = ; 10. n =15, / 2 α = 0.025. Then df = n -1 =14 and 2 14, 0.975 χ = 5.629 UCL= ( 29 ( 29 2 2 2 2 2 1,1 /2 1 14 46 850.783 29.168 5.629 n n s s s s α χ - - - = = = = . 11. 55, 5633, 64, 4793, 2 117 x x y y x y n s n s df n n = = = = = + - = , / 2 117,0.025 120,0.025 1.9799 df t t t α = = , and 2 2 2 [( 1) ( 1) ]/( 2) p x x y y x y s n s n s n n = - + - + - = 270,149,29. Then, ( 29 ( 29 2 2 2, / 2 / / x y n n p x p y x y t s n s n α + - - + = (47,520 – 44,304) . 1.9799 (955.66) = 3216 . 1892.11 or 1323.89 < x y μ μ - < 5108.11 12. a. The degrees of freedom are given by 2 2 2 2 2 2 2 1 2 1 2 1 2 1 2 1 2 /( 1) /( 1) s s s s n n n n n n ν � � � � � � � � = + - + - ˆ � � � � � � � � � � � � � � � � 19 b. The degrees of freedom are given by 2 2 2 2 2 2 2 1 2 1 2 1 2 1 2 1 2 /( 1) /( 1) s s s s n n n n n n ν � � � � � � � � = + - + - ˆ � � � � � � � � � � � � � � � � 9

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c. The degrees of freedom are given by 2 2 2 2
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