lec01-203-07-int-math

lec01-203-07-int-math - 1-12.54 cm = 1in. : 12 in. = 1 ft...

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Unformatted text preview: 1-12.54 cm = 1in. : 12 in. = 1 ft :3 ft= 1 yrd.unit conversion- mole method60 mi/hr= ? m/s1-1.1Measuring AnglesRcircumference = 2R(radians) = R(degrees)= (radians) 3602 R1cos()sin()/22unit circle3/290180270360sin2() + cos2()=11-1.2unit circle[cos(),sin()][+,+][-,+][-,-][+,-]abca2+b2=c2a csin() =ccos() =b btan() =a b a c= sin-1( )c= cos-1( )b= tan-1( )a a = c sin()b = c cos()1-1.3final positiontimexftfxitipositioncoordinate (x) measure of positiontime (t)one dimension how far what direction + or -average velocityifxxx=displacement ififttxxtxv==initial positiontime how fast what direction + or -magnitudedirection1-2xccavector (position and displacement)- magnitude (length) - directionfinal positiontimextf(xf, yf)tiinitial positiontime(xi, yi)ytwo dimensionsirfrifrrr =1-3(x, y)rx = r cos()rposition vector- magnitude (length) - direction2 ways to represent position x-diry-dirry = r sin(...
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This note was uploaded on 09/22/2008 for the course PHYSICS 203 taught by Professor Croft during the Spring '08 term at Rutgers.

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lec01-203-07-int-math - 1-12.54 cm = 1in. : 12 in. = 1 ft...

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