Determination of a Chemical Formula

Determination of a Chemical Formula - Determination of a...

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Determination of a Chemical Formula Objective: To study stoichiometry by determining the percent composition and simplest formula for an oxide of copper by it’s reduction with methane gas. Experimental data: Part A: Mass of large test tube: 17.2 g. Mass of test tube + copper oxide: 19.3 g. Mass of copper oxide: 2.1 g. Part B: Mass of copper + test tube (after the reaction): 18.8 g. Mass of copper: 1.60 g. Sample Calculations: Mass of copper: the difference of the test tube + the copper and just the test tube 18.8 g. – 17.2 g. = 1.60 g. Cu Mass percentage of copper in the oxide: mass of Cu x (100) mass of CuO 1.60 g. x (100) = 76.2% Cu 2.1 g. Mass of oxygen: mass of CuO – mass of Cu 2.1 g. – 1.60 g. = 0.5 g. O Mass percentage of oxygen in the oxide: mass of O x (100) mass of CuO 0.5 g. x (100) = 23.8% O 2.1 g. Moles of copper in the oxide: mass percent molar mass 76.2 g. = 1.20 mol Cu 63.546g. Moles of oxygen in the oxide: mass percent
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Determination of a Chemical Formula - Determination of a...

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