problemset6solution - PAM 210 Lecture 1 Spring 2008 Problem...

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PAM 210 Lecture 1 Spring 2008 Problem Set #6 Posted: 10 th of March, 2008 Due date: 24 th of March, 2008 Round all final answers to four decimal places, if necessary. #1)A college decides to admit 1400 students. Past experience shows that 60% of the students admitted will accept. Assuming that students make their decisions independently, the number who accept has the B(1400, 0.6) distribution. a) What are the mean and standard deviation of the number X of students who accept? The mean of X is 840 6 . 0 * 1400 = = = np X μ The standard deviation of X is 3303 . 18 4 . 0 * 6 . 0 * 1400 ) 1 ( = = - = p np X σ b) What is the probability that more than 850 accept? Round your value of z up to two decimal places and then use Table A. We need to find out the z-score. 55 . 0 3303 . 18 840 850 = - = z 2912 . 7088 . 1 ) 55 . 0 ( 1 ) 55 . 0 ( ) 850 ( = - = - = = z P z P X P
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#2) An experiment on the teaching of reading compares two methods, A and B. The response variable is the Degree of Reading Power (DRP) score. The experimenter uses Method A in a class of 26 students and Method B in a comparable class of 24 students. The classes are assigned to the teaching methods at random.
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problemset6solution - PAM 210 Lecture 1 Spring 2008 Problem...

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