EEE206_2003_Solutions

EEE206_2003_Solutions - Solutions to EEE206, Spring...

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Solutions to EEE206, Spring Semester 2003 1. (a) Improvement in signal to noise ratio Ease of radiation in radio systems, since efficient radiation from an antenna requires its length to be λ /4 Use different carrier frequencies to separate signals with similar baseband frequencies Facilitates multiplexing (b) For AM, m = E m / E c m should be kept less than 1 to avoid 'splatter' in output spectrum (c) (i)Total power = P c (1+m 2 /2) = 5 x 10 3 when m = 1 Hence carrier power = 3.33 x 10 3 watts (ii) m = 0.85 Power in one sideband = m 2 P c /4 = 0.85 x 0.85 x 0.25 x 3.33 x 10 3 = 601.5 watts if P RC = power in reduced carrier, 10 log 10 (P c / P RC ) = 25, hence P RC = 10.5 watts Total output power = 10.5 + 602 = 612 watts (d) m 1 = 0.7, m 2 = 0.5 and m 3 = 0.2 Composite m = (0.7 2 + 0.5 2 + 0.2 2 ) = 0.883 Total power output = 3.33 x 10 3 (1 + .883 2 / 2) = 4.633 x 10 3 watts 2 (a) Diagram should show a single superhet circuit with RF amp, mixer, LO, IF amp, demodulator, AF amp and LS. The demodulation process should be explained with the aid of
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EEE206_2003_Solutions - Solutions to EEE206, Spring...

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